Unit 4 of 4 · B.Com Sem 6

Unit 4: Replacement & inventory models

Operation Research notes · PTU syllabus (BCOM 602-18)

3 min read4 topics10 exam questions
On this page
  1. Unit summary
  2. Replacement of items that deteriorate with time
  3. Items that fail suddenly: individual and group replacement
  4. Inventory costs and the basic EOQ model
  5. Other deterministic models
  6. Key terms
  7. Quick revision
  8. Important questions

Unit summary

Machines wear out and stocks must be replenished — both involve cost trade-offs. This unit covers replacement of items that deteriorate with time, individual and group replacement of items that fail suddenly, inventory costs, and deterministic inventory models with uniform and non-uniform demand and with infinite or finite production rates.

After this unit you can

  • Determine the optimal replacement age for deteriorating items
  • Compare individual and group replacement policies
  • Explain inventory costs and the EOQ model
  • Apply EOQ models with shortages and finite production (EPQ)

PTU syllabus topics

  • Replacement of items that deteriorate with time
  • individual and group replacement policy for items that fail suddenly
  • inventory costs
  • deterministic demand models with uniform and non-uniform demand and finite/infinite production rates
Key formulasInventory and replacement
  • EOQ

    √(2DS / H)

    D = demand, S = order cost, H = holding cost

  • Number of orders

    D / EOQ

  • Total inventory cost

    (D/Q)S + (Q/2)H

  • Replace when

    Average annual cost is at its minimum

1

Topic 1

Replacement of items that deteriorate with time

  • Maintenance cost rises with age while capital cost per year falls; replace when the average annual total cost is minimum.
Key formulasReplacement (money value constant)
  • Average annual cost for n years

    [C − S + Σ maintenance costs for n years] ÷ n

  • Replacement rule

    Replace at the end of year n when the next year's maintenance cost exceeds the current average annual cost

YearMaintenanceCumulative maintenanceC − S (₹12,000 − resale)Total costAverage cost
11,0001,00012,000 − 9,000 = 3,0004,0004,000
21,5002,50012,000 − 7,000 = 5,0007,5003,750
32,0004,50012,000 − 6,000 = 6,00010,5003,500
42,5007,00012,000 − 5,500 = 6,50013,5003,375
53,50010,50012,000 − 5,000 = 7,00017,5003,500
  • Average cost is minimum (₹3,375) at 4 years → replace every 4 years.
  • With time value of money: compare the weighted average (discounted) annual costs.
2

Topic 2

Items that fail suddenly: individual and group replacement

  • Items like bulbs and tubes fail completely; failure probabilities are known from life tables.
  • Individual replacement: replace each item as it fails.
  • Group replacement: replace all items at fixed intervals (whether failed or not) and individually replace failures in between — cheaper when individual replacement cost is much higher than group cost per unit.
Key formulasIndividual vs group replacement
  • Expected life

    Σ (life × probability of failure at that age)

  • Average failures per period (individual)

    N ÷ Expected life

  • Individual policy cost per period

    (N ÷ mean life) × individual replacement cost

  • Group policy cost per period at t

    [N × group cost + Σ failures up to t × individual cost] ÷ t

  • Rule: group replacement at the end of period t if the cost of individual replacement in the next period is greater than the average cost per period up to t.

Example

1,000 bulbs; individual replacement ₹10 each, group replacement ₹4 each; mean life 2.5 months → individual policy ≈ 1,000 ÷ 2.5 × 10 = ₹4,000 per month. If group replacement every 2 months costs ₹3,200 per month (including in-between failures), group replacement is better.

3

Topic 3

Inventory costs and the basic EOQ model

ClassificationInventory costs
Inventory costs
  • Ordering (set-up) cost

    Placing and receiving orders, machine set-up

  • Carrying (holding) cost

    Storage, insurance, interest, obsolescence

  • Shortage (stock-out) cost

    Lost sales, goodwill, backorder costs

  • Purchase (unit) cost

    Price paid, affected by discounts

Model I: uniform demand, infinite (instantaneous) replenishment, no shortages

Key formulasEOQ model
  • Economic order quantity

    Q* = √(2DS ÷ H)

  • Number of orders

    D ÷ Q*

  • Cycle time

    Q* ÷ D

  • Minimum total variable cost

    √(2DSH)

Example

D = 9,000 units a year, S = ₹200 per order, H = ₹4 per unit per year. Q* = √(2 × 9,000 × 200 ÷ 4) = √9,00,000 ≈ 949 units; orders ≈ 9.5 a year; total variable cost = √(2 × 9,000 × 200 × 4) ≈ ₹3,795.

4

Topic 4

Other deterministic models

Model II: finite production rate (EPQ), no shortages

Key formulasEconomic production quantity
  • EPQ

    Q* = √[2DS ÷ (H (1 − d ÷ p))] — d demand rate, p production rate

  • Maximum inventory

    Q* (1 − d ÷ p)

Model III: uniform demand with planned shortages (backorders)

Key formulasEOQ with shortages
  • Optimal order quantity

    Q* = √(2DS ÷ H) × √[(H + B) ÷ B] — B shortage cost per unit per year

  • Maximum shortage

    Q* × H ÷ (H + B)

Non-uniform demand and quantity discounts

  • Non-uniform demand within a cycle (demand varying across periods): use period-by-period methods or treat average demand; with known patterns, use the total demand over the cycle in place of uniform demand.
  • Quantity discounts: compute EOQ at each price; if EOQ is not feasible for that price break, use the minimum quantity of the break; choose the quantity with the lowest total cost (purchase + ordering + carrying).

Exam tip

Always state the assumptions of each inventory model before solving — they carry marks.

Key terms

Replacement policy
Rule for when to replace equipment to minimise cost
Group replacement
Replacing all items at fixed intervals plus individual failures in between
EOQ
Order size minimising ordering and carrying costs
EPQ
Economic production quantity with finite production rate
Backorder
Unmet demand satisfied later from the next replenishment

Quick revision

  • Deteriorating items: replace when average annual cost is minimum.
  • Sudden failure: compare individual vs group replacement costs.
  • Inventory costs: ordering, carrying, shortage, purchase.
  • EOQ = √(2DS/H); EPQ adds (1 − d/p); shortages add √[(H + B)/B].
  • Quantity discounts: compare total cost at each price break.

Important exam questions

Practice questions written to the PTU exam pattern for this unit's syllabus: short answers (Section A style) and long answers (Sections B and C style).

Short-answer questions

  1. Q1.When should a deteriorating machine be replaced?
  2. Q2.What is group replacement?
  3. Q3.State the assumptions of the EOQ model.
  4. Q4.Write the EPQ formula.
  5. Q5.What is a backorder?
  6. Q6.How are quantity discounts handled in inventory models?

Long-answer questions

  1. Q1.Explain the replacement policy for items that deteriorate with time with an illustration.
  2. Q2.Explain individual and group replacement policies for items that fail suddenly.
  3. Q3.Explain inventory costs and derive the EOQ formula.
  4. Q4.Explain inventory models with finite production rate and shortages.

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